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Program to Multiply Two 16 Bit Numbers

May 4, 2011 by ProjectsGeek 2 Comments

Objective

Multiply Two 16 Bit Numbers

Write a Program to Multiply Two 16 Bit Numbers in Assembly language . Program will ask for two numbers to be multiplied and should store those numbers in AX and BX Registers . Now it should implement certain logic to both numbers to find the result.
Consider that a word of data is present in the AX register and 2nd word of data is present in the BX register. We have to multiply the word in AX with the word in BX. Using MUL instruction, multiply the contents of the 2 registers. The multiplication of the two 16 bit numbers may result into a 32 bit number. So result is stored in the DX and AX register.
The MSB of result is stored in the DX register and LSB of result in AX register.

 

AX = 1234 H
1234 H
BX = 0100 H
´
0100 H
23400 H

 

Algorithm to Multiply Two 16 Bit Numbers

Step I       :    Initialize the data segment.
Step II     :    Get the first number in AX register.
Step III   :    Get the second number in BX register.
Step IV    :    Multiply the two 16 bit numbers.
Step V     :    Display the result.
Step VI    :    Stop

Multiply Two 16 Bit Numbers Flow Diagram

Program to Multiply Two 16 Bit Numbers 1

Program to Multiply Two 16 Bit Numbers

 .model small  
 .data        
 a dw 1234H  
 b dw 0100H  
 .code  
      mov      ax, @data      ; Initialize data section  
      mov      ds, ax  
      mov      ax, a          ; Load number1 in ax  
      mov      bx, b          ; Load number2 in bx  
      mul      bx             ; multiply numbers. Result in dx and ax  
      mov      si, ax  
      mov      bx, dx         ; Result in reg bx  
      mov      dh, 2  
 l1:     mov      ch, 04h     ; Count of digits to be displayed  
      mov      cl, 04h        ; Count to roll by 4 bits    
 l2:     rol      bx, cl          ; roll bl so that msb comes to lsb   
      mov      dl, bl         ; load dl wth data to be displayed  
      and      dl, 0fH        ; get only lsb  
      cmp      dl, 09         ; check if digit is 0-9 or letter A-F  
      jbe      l4  
      add      dl, 07         ; if letter add 37H else only add 30H  
 l4:     add      dl, 30H  
      mov      ah, 02         ; Function 2 under INT 21H (Display character)  
      int      21H  
      dec      ch             ; Decrement Count  
      jnz      l2  
      dec      dh  
      cmp      dh, 0  
      mov      bx, si       
      jnz      l1  
      mov      ah, 4cH        ; Terminate Program  
      int      21H  
      end

 

How to Run this Program

For Running this program you should have installed Tasm on you computer . If you have not installed Tasm  yet please install from Here . More assembly language codes can be found here.

C:\programs>tasm 16-mul.asm
Turbo Assembler Version 3.0 Copyright (c) 1988, 1991 Borland International
Assembling file: 16-mul.asm
Error messages: None
Warning messages: None
Passes: 1
Remaining memory: 438k
C:\programs>tlink 16-mul
Turbo Link Version 3.0 Copyright (c) 1987, 1990 Borland International
Warning: No stack
C:\programs>16-mul
00123400

Other Projects to Try:

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  2. Multiply Two 8 Bit BCD Numbers
  3. Multiply Two 8 Bit Numbers using Add and Shift Method
  4. Multiply Two 8 Bit Numbers Successive Addition Method
  5. Multiply Two 8 Bit Numbers in Assembly Language

Filed Under: Assembly Codes Tagged With: Assembly Codes

Reader Interactions

Comments

  1. Rambo says

    April 9, 2012 at 7:12 pm

    It’s Label

    Reply
  2. Master says

    October 18, 2011 at 8:19 pm

    where is l4 ?

    Reply

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