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Fundamentals of Datastructure

SE(IT) FDS (Fundamentals of Data structure) Practicals or Assignments

May 1, 2012 by ProjectsGeek Leave a Comment

SE(IT) FDS (Fundamentals of Data structure) Practicals or Assignments
Below is the list of all Practicals of SE-IT FDS subject with Source code . Fundamentals of Data structure subjects is one of the compulsory subject in SE-IT semester -1 under Pune University and Mumbai University .
 
PROGRAM TO PERFORM VARIOUS OPERATIONS ON SETS
Program Code
PROGRAM TO PERFORM VARIOUS OPERATIONS ON STRINGS
Program Code
Write a program to perform VARIOUS OPERATION IN SIMPLE MATRIX
Program Code
Database in C
Program Code
Write a program to perform Double Link List
Program Code
Write a program to perform Single Link List
Program Code
Write a program to perform Sparse Matrix Operations  in C
Program Code
Program for Mobile user information
Program Code
Program for Operations on a database without using pointers
Program Code
Write a program to perform String operationswith pointers
Program Code
Write a program to perform Set operations – Union,Difference
Intersection ,Symmetric Difference etc.
Program Code
Write a program to perform various string operations such as Copy, Length, Reversing, Palindrome, Concatenation.
Program Code
Write a program to perform operations on matrices like addition,saddle point, magic square ,inverse & transpose .
Program Code

 

Other Projects to Try:

  1. Operations on matrices like addition, multiplication, saddle point, magic square ,inverse & transpose
  2. Data Structure and Files Program Codes
  3. Fundamentals of Programming Languages Codes
  4. Software Design Laboratory Assignments
  5. Software Development Tools Lab TE(Sem-II) practical Assignments

Filed Under: Fundamentals of Datastructure Tagged With: Datastructure Assignments

Operations on matrices like addition, multiplication, saddle point, magic square ,inverse & transpose

September 9, 2011 by ProjectsGeek Leave a Comment

Write a program to perform operations on matrices like addition, multiplication, saddle point, magic square ,inverse & transpose etc using functions & pointers. 


#include
#include
#include
#include void main()
{
int m1[30][30],m2[30][30],m3[30][30]={0};
int i,j,x,k,r1,r2,c1,c2,n,ch,sum=0;
char wish,y;
clrscr();
printf(“enter no of row for 1st matrix”);
scanf(“%d”,&r1);
printf(“enter no of col for 1st matrix”);
scanf(“%d”,&c1);
for(i=0;i<r1;i++)
for(j=0;j<c1;j++)
{
printf(“\n\t\t enter a[%d][%d]:”,i,j);
scanf(“%d”,&m1[i][j]);
}
printf(“enter no of row for 2nd matrix”);
scanf(“%d”,&r2);
printf(“enter no of col for 2nd matrix”);
scanf(“%d”,&c2);
for(i=0;i<r2;i++)
for(j=0;j<c2;j++)
{
printf(“\n\t\t enter a[%d][%d]:”,i,j);
scanf(“%d”,&m2[i][j]);
}
menu:
printf(“\n for sum of matrix press 1”);
printf(“\n for mutiplication of matrix press 2”);
printf(“\n for transpose of 1st matrix  press 3”);
printf(“\n for cheaking symatericness of 1st matrix  press 4”);
printf(“\n for cheaking sqew symatry  matrix press 5\n”);
scanf(“%d”,&ch);
switch(ch)
{
case 1://addition
if((r1==r2)&&(c1==c2))
for(i=0;i<r1;i++)
{
for(j=0;j<c1;j++)
m3[i][j]=m1[i][j]+m2[i][j];
}
else
{
exit(0);
}
for(i=0;i<r1;i++)
{
printf(“\n”);
for(j=0;j<c1;j++)
printf(“\t\t%d”,m3[i][j]);
}
break;
case 2://multiplication
sum=0;
if(c1==r2)
{
for(i=0;i<r1;i++)
{
printf(“\n”);
for(j=0;j<c2;j++)
{
for(k=0;k<c1;k++)
{
sum+=(m1[i][k]*m2[k][j]);
}
printf(“\t\t%d”,sum);
sum=0;
}
}
}
else
exit(0);
break;
case 3:
for(i=0;i<r1;i++)
{
for(j=0;j<c1;j++)
{
m3[j][i]=m1[i][j] ;
}
}
for(i=0;i<r1;i++)
{
for(j=0;j<c1;j++)
{
printf(“\t\t%d”,m3[i][j]);
}
printf(“\n”);
}
break;
case 4:
/*int flag=0;
for(i=0;i<r1;i++)
{
for(j=0;j<c1;j++)
m3[j][i]=m1[i][j];
}
for(i=0;i<r1;i++)
{
for(j=0;j<c1;j++)
{
if(m3[i][j]==m1[i][j])
flag++;
}
}
if(flag==r1*c1)
printf(” 1st matrix  is symatric”);
else
printf(” 1st matrix  is not symatric”);*/
int flag=1;
for(i=0;i<r1;i++)
{
for(j=i+1;j<c1;j++)
{
if(m1[i][j]!=m1[j][i])
{
flag=0;
}
}
}
if(flag==1)
printf(” 1st matrix  is symatric”);
else
printf(” 1st matrix  is not symatric”);
break;
case 5://skew symatric
int fl=0;
for(i=0;i<r1;i++)
{
for(j=0;j<c1;j++)
m3[j][i]=m1[i][j];
}
for(i=0;i<r1;i++)
{
for(j=0;j<c1;j++)
{
if(m3[i][j]==-m1[i][j])
fl++;
}
}
if(fl==r1*c1)
printf(” 1st matrix  is skew symatric”);
else
printf(” 1st matrix  is not  skew symatric”);
}
getch();
}//prg terminates

 

Other Projects to Try:

  1. Matrix Operations with Pointers
  2. Set operations – Union, Intersection, Difference, Symmetric Difference using C
  3. Matrix Operations in C Language
  4. Sparse Matrix Operations Code using C Langauge
  5. Multiply Two 8 Bit Numbers Successive Addition Method

Filed Under: Fundamentals of Datastructure Tagged With: Datastructure Assignments

string operations such as Copy, Length, Reversing, Palindrome, Concatenation

September 9, 2011 by ProjectsGeek Leave a Comment

Write a program to perform various string operations such as Copy, Length, Reversing, Palindrome, Concatenation
#include
#include
#include
void main()
{
int  no,m,ch ,i,j,n,k,flag=0;
char str[20],str2[20],str3[20],str4[20];
char wish;
clrscr();
do
{
menu:
printf(“\n1.length of the string.”);
printf(“\n2.copying string another.”);
printf(“\n3.concatination of two string”);
printf(“\n4.reversing the string”);
printf(“\n5.checking palindrome or not.”);
printf(“\n6.checking sub-string in the string.” );
printf(“\nEnter the choice:”);
scanf(“%d”,&ch);
switch(ch)
{
case 1:
printf(“Enter the string: “);
flushall();
gets(str);
for(i=1;str[i]!=’\0′;i++); //to find the length of the string
printf(“the length of the string is:%d “,i);
break;
case 2:
printf(“Enter the string: “);
flushall();
gets(str);
for(i=0;str[i]!=’\0′;i++)//TO COPY A STRING IN OTHER
{
str2[i]=str[i];
}
str2[i]=’\0′;
printf(“\n the copied string is: “);
puts(str2);
break;
case 3:
printf(“Enter the string: “);
flushall();
gets(str);
printf(“\n Enter the second string”);
flushall();
gets(str2);
i=0;
while(str[i]!=’\0′)
i++;
for(j=0;str2[j]!=’\0′;j++,i++)//TO CONCATINATE TWO STRING
str[i]=str2[j];
str[i]=’\0′;
printf(“\nthe concatinated string is: “);
puts(str);
break;
case 4:
printf(“Enter the string: “);
flushall();
gets(str);
i=0;
while(str[i]!=’\0′)
i++;
i–;
for(j=0;str[j]!=’\0′,i>=0;j++,i–)//TO REVERSE STRING
str2[j]=str[i];
str2[j]=’\0′;
printf(“\n the reverse string is: “);
puts(str2);
break;
case 5:
printf(“Enter the string: “);
flushall();
gets(str);
i=0;
while(str[i]!=’\0′)
i++;
i–;
flag=1;
for(j=0;i>j;j++,i–)
{ 

if(str[i]!=str[j])
{
flag=0;
break;
}
}
if(flag==1)
printf(“\nthe string is palindrom.”);
else
printf(“\nthe string is not palindrom.”);
break;
case 6:
printf(“Enter the string: “);
flushall();
gets(str);
printf(“\nEnter the second string: “);  //TO FIND WETHER SUBSTRING EXISTS OR NOT
gets(str4);
for(m=0;str[m]!=’\0′;m++);
for(k=0;k<=m-1;k++)
{
for(j=0;str4[j]!=’\0′;j++)
{
if(str[k+j]!=str4[j])
{
flag=0;
break;
}
}
if(str4[j]==’\0′)
{
flag=1;break;}
}
if(flag==1)
printf(“\nsubstring found at position:%d “,j+k);
else
printf(“\n substring donot exists”);
break;
default:
printf(“\n wrong choice!!!!”);
break;
}
printf(“\nwant to continue(y/n)”);
scanf(“%c”,&wish);
}
while(wish!=’n’);
getch();
}

Other Projects to Try:

  1. Set operations – Union, Intersection, Difference, Symmetric Difference using C
  2. String Operations with Pointers
  3. String Operations in C Program
  4. Factorial,Greatest Number,String Palindrome Shell code
  5. String Operations in C Language

Filed Under: Fundamentals of Datastructure Tagged With: Datastructure Assignments

Set operations – Union, Intersection, Difference, Symmetric Difference using C

September 9, 2011 by ProjectsGeek Leave a Comment

Write a program to perform Set operations – Union, Intersection, Difference,
Symmetric Difference etc.
#include
#include
#include void main()
{
int i,j,k,p,ch,n1,n2,set1[10],set2[10], set3[20],flag;
char wish;
clrscr();
do
{
printf(“press 1 for union”);
printf(“\npress 2 for intersection”);
printf(“\npress 3 for subtraction”);
printf(“\n enter ur choice”);
scanf(“%d”,&ch);
switch(ch)
{
case 1://for union
printf(“\nenter the size of set1\n”);
scanf(“%d”,&n1);
printf(“enter the element of set1\n”);
for(i=0;i<n1;i++)
scanf(“%d”,&set1[i]);
printf(“enter the size of set2\n”);
scanf(“%d”,&n2);
printf(“enter the elements of set2\n”);
for(i=0;i<n2;i++)
scanf(“%d”,&set2[i]);
k=0;
for(i=0;i<n1;i++)
{
set3[k]=set1[i];
k++;
}
for(i=0;i<n2;i++)
{
flag=1;
for(j=0;j<n1;j++)
{
if(set2[i]==set1[j])
{
flag=0;
break;
}
}
if(flag==1)
{
set3[k]=set2[i];
k++;
}
}
p=k;
for(k=0;k <p;k++)
 

{
printf(” %d”,set3[k]);
} 

break;
case 2: //for intersection
printf(“enter the size of sets1”);
scanf(“%d”,&n1);
printf(“enter the element of set1”);
for(i=0;i<n1;i++)
scanf(“%d”,&set1[i]);
printf(“enter the size of sets2”);
scanf(“%d”,&n2);
printf(“enter the elements of set2”);
for(i=0;i<n2;i++)
scanf(“%d”,&set2[i]);
k=0;
for(i=0;i<n2;i++)
{
flag=1;
for(j=0;j<n1;j++)
{
if(set2[i]==set1[j])
{
flag=0;
break;
}
}
if(flag==0)
{
set3[k]=set2[i];
k++;
}
}
p=k;
for(k=0;k <p;k++)

{
printf(” %d”,set3[k]); 

}
break;
case 3://for subtraction
printf(“enter the size of sets1”);
scanf(“%d”,&n1);
printf(“enter the element of set1”);
for(i=0;i<n1;i++)
scanf(“%d”,&set1[i]);
printf(“enter the size of sets2”);
scanf(“%d”,&n2);
printf(“enter the elements of set2”);
for(i=0;i<n2;i++)
scanf(“%d”,&set2[i]);
k=0;
for(i=0;i<n1;i++)
{
flag=1;
for(j=0;j<n2;j++)
{
if(set1[i]==set2[j])
{
flag=0;
break;
}
}
if(flag==1)
{
set3[k]=set1[i];
k++;
}
}
p=k;
for(k=0;k <p;k++)

{
printf(” %d”,set3[k]); 

}
break;

}

printf(“\n want to continue: “);
flushall();
scanf(“%c”,&wish);
}
while(wish!=’n’);
} //prg terminates

Other Projects to Try:

  1. Operations on matrices like addition, multiplication, saddle point, magic square ,inverse & transpose
  2. string operations such as Copy, Length, Reversing, Palindrome, Concatenation
  3. Bitwise Operations using C++
  4. Matrix Operations with Pointers
  5. String Operations with Pointers

Filed Under: Fundamentals of Datastructure Tagged With: Datastructure Assignments

String Operations with Pointers

June 26, 2011 by ProjectsGeek Leave a Comment

String operations with pointers

Program showing various operations on string(functions implemented
with pointers).
functions implemented:
(1) Reversing a string
(2) Palindrome
(3) Copy
(4) String comparison
(5) Searching a string(substring)

Source Code

 #include  
 #include  
 #include  
 #include  
 /*function prototypes*/  
 void reverse(char *a);  
 int palindrome(char *a);  
 void copy(char *b,char *a);  
 int compare(char *a,char *b);  
 void search(char *a,char *b);  
 void main()  
 { char a[100],b[100];  
 int result,op;  
 clrscr();  
 do  
 { /* display the menu */  
 printf("\n1)Reverse the Given String");  
 printf("\n2)Check for palindrome");  
 printf("\n3)Copy");  
 printf("\n4)String Comparison");  
 printf("\n5)String Searching(substring)");  
 printf("\n6)Quit");  
 printf("\n\nEnter Your Choice:");  
 scanf("%d",&op);  
 flushall();  
 switch(op)  
 {  
 case 1: printf("\n Enter a String:");  
 gets(a);  
 reverse(a);  
 printf("\n Result=%s",a);  
 printf("\n\n press a Character !!!!!!");  
 getch();  
 break;  
 case 2: printf("\n Enter a String:");  
 gets(a);  
 result=palindrome(a);  
 if(result==0)  
 printf("\nNot a palindrome");  
 else  
 printf("\nA palindrome");  
 printf("\n\n press a Character !!!!!!");  
 getch();  
 break;  
 case 3: printf("\n Enter a String:");  
 gets(a);  
 copy(b,a);  
 printf("\nResult=%s",b);  
 printf("\n\n press a Character !!!!!!");  
 getch();  
 break;  
 case 4: printf("\n Enter 1st string:");  
 gets(a);  
 printf("\n Enter 2nd string:");  
 gets(b);  
 result=compare(a,b);  
 if(result==0)  
 printf("\nboth are same");  
 else  
 if(result>0)  
 printf("\n1st>2nd");  
 else  
 printf("\n1st<2nd");  
 printf("\n\n press a Character !!!!!!");  
 getch();  
 break;  
 case 5: printf("\n Enter 1st string:");  
 gets(a);  
 printf("\n Enter 2nd string:");  
 gets(b);  
 search(a,b);  
 printf("\n\n press a Character !!!!!!");  
 getch();break;  
 }  
 }while(op!=6);  
 }  
 void reverse(char *a)  
 { char *p,*q;  
 char temp;  
 /* Algorithm used is an inplace Algorithm  
 1. q is postioned on the last character  
 2. p is postioned on the first character  
 3. *p is interchanged with *q  
 4. p is increased by 1 and q is decremented by 1  
 5. if p"""  
 */  
 p=q=a;  
 while(*q!='\0')  
 q++;  
 /* q is on the null character*/  
 q--;  
 while(p /* Algorith used  
 1. q is positioned on the last character  
 2. p is positioned on the first character  
 3. if *p != *q then it is not a palindrome,return(0)  
 4. p is increased by 1 and q is decremented by 1  
 5. if p"""  
 6. string is a palindrome , return(1)  
 */  
 p=q=a;  
 while(*q!='\0')  
 q++;  
 /* q is on the null character*/  
 q--;/*q is on the last character*/  
 while(p /* Algorithm  
 1.both the strings are compared,character by character  
 from the beginning  
 2.on first point of mismatch:  
 a.if(*a>*b) then a>b  
 b.if(*a  
 3. if both the strings end together then they are eqaul  
 */  
 while(*a!='\0')  
 {  
 if(*a > *b)  
 return(1);  
 if(*a < *b)  
 return(-1);  
 a++;b++;  
 }  
 return(0);  
 }  
 void search(char *a ,char *b)  
 { int lena,lenb;  
 char *i,*j,*k;  
 /*Algorithm  
 1. lenb=length of string b[],lena=length of a[]  
 string a[] is scanned using the pointer i from location  
 0 to length of a[]-lenb+1  
 2. string b[] is matched in string a[] from the position i  
 */  
 for(lena=0;*(a+lena)!='\0';lena++)  
 ;  
 for(lenb=0;*(b+lenb)!='\0';lenb++)  
 ;  
 /* searching */  
 for(i=a;i<=a+lena-lenb+1;i++)  
 { k=i;  
 for(j=b;*k==*j&& *j!='\0';j++,k++)  
 ;  
 if(*j=='\0')  
 printf("\nstring found at location:%d",i-a+1);  
 }  
 }  
 ""  

String operations with pointers Output

1)Reverse the Given String
2)Check for palindrome
3)Copy
4)String Comparison
5)String Searching(substring)
6)Quit

Enter Your Choice:1

Enter a String:India

Result=aidnI

press a Character !!!!!!
1)Reverse the Given String
2)Check for palindrome
3)Copy
4)String Comparison
5)String Searching(substring)
6)Quit

Enter Your Choice:2

Enter a String:India

Not a palindrome

press a Character !!!!!!
1)Reverse the Given String
2)Check for palindrome
3)Copy
4)String Comparison
5)String Searching(substring)
6)Quit

Enter Your Choice:2

Enter a String:madam

A palindrome

press a Character !!!!!!

1)Reverse the Given String
2)Check for palindrome
3)Copy
4)String Comparison
5)String Searching(substring)
6)Quit

Enter Your Choice:3

Enter a String:Asia

Result=Asia

press a Character !!!!!!
1)Reverse the Given String
2)Check for palindrome
3)Copy
4)String Comparison
5)String Searching(substring)
6)Quit

Enter Your Choice:4

Enter 1st string:India

Enter 2nd string:Asia

1st>2nd

press a Character !!!!!!
1)Reverse the Given String
2)Check for palindrome
3)Copy
4)String Comparison
5)String Searching(substring)
6)Quit

Enter Your Choice:5

Enter 1st string:Pacific

Enter 2nd string:c

string found at location:3
string found at location:7

press a Character !!!!!!
1)Reverse the Given String
2)Check for palindrome
3)Copy
4)String Comparison
5)String Searching(substring)
6)Quit

Enter Your Choice:6

Other Projects to Try:

  1. Database Operations without pointers source code
  2. String Operations in C Program
  3. Matrix Operations with Pointers
  4. string operations such as Copy, Length, Reversing, Palindrome, Concatenation
  5. String Operations in C Language

Filed Under: Fundamentals of Datastructure Tagged With: Datastructure Assignments

Database Operations without pointers source code

June 26, 2011 by ProjectsGeek Leave a Comment

Database Operations without pointers

Objective

Program for Operations on a database without using pointers. This program in c/c++ will simulate database operations such as create record, insert, delete, search, print, sort and modify records using simple menu interface which is provided to interact with the program.
Program developed using c/c++ starts with menu options where user can provide data such as employee details. User needs to provide number of employees we want to insert into the database. After entering number of employees we want to insert user can provide data inform of employee name, employee id, salary for particular employee. As soon as entered is pressed record will be inserted into database.
For more c programs check here.
Database Operations without pointers
 #include  
 #include  
 #include  
 typedef struct employee  
 { int code;  
 char name[20];  
 int salary;  
 }employee;  
 void insert(employee st[],int position,int n);  
 void Delete(employee st[],int position,int n);  
 int search(employee st[],int code,int n);  
 void print(employee st[],int n);  
 void read(employee st[],int n);  
 void sort(employee st[],int n);  
 void modify(employee st[],int n);  
 void main()  
 { employee st[30];  
 int n,i,op,position,code;  
 clrscr();  
 do{  
 flushall();  
 printf("\n1)create\n2)insert\n3)delete\n4)search\n5)print\n6)Sort\n7)Modify");  
 printf("\n8)Quit");  
 printf("\nEnter Your Choice:");  
 scanf("%d",&op);  
 switch(op)  
 { case 1: printf("\nEnter No. of employees:");  
 scanf("%d",&n);  
 read(st,n);  
 break;  
 case 2: printf("\n enter the position(no of records=%d):",n);  
 scanf("%d",&position);  
 if(position<=n+1)  
 {  
 insert(st,position,n);  
 n++;  
 print(st,n);  
 }  
 else  
 printf("\n can not insert");  
 break;  
 case 3:printf("\n enter the code : ");  
 scanf("%d",&code);  
 position=search(st,code,n);  
 if(position != -1 )  
 {  
 Delete(st,position,n);  
 n--;  
 print(st,n);  
 }  
 else  
 printf("\n can not delete ");  
 break;  
 case 4: printf("\nenter code:");  
 scanf("%d",&code);  
 position=search(st,code,n);  
 if(position==-1)  
 printf("\nnot found");  
 else  
 { printf("\n found at location=%d",position+1);  
 printf("\n %s\t%d\t%d",st[position].name,st[position].code,st[position].salary);  
 }  
 break;  
 case 5: print(st,n);  
 break;  
 case 6: sort(st,n);print(st,n);break;  
 case 7: modify(st,n);print(st,n);break;  
 }  
 }while(op!=8);  
 }  
 void insert( employee st[],int position,int n)  
 { int i;  
 printf("\n enter data(name code salary): ");  
 for(i=n-1;i>=position-1;i--) /*index is 1 less than position*/  
 st[i+1]=st[i];  
 scanf("%s%d%d",st[position-1].name,&st[position-1].code,&st[position-1].salary);  
 }  
 void Delete(employee st[],int position,int n)  
 { int i;  
 for(i=position+1;i st[j+1].code)  
 {  
 temp=st[j];  
 st[j]=st[j+1];  
 st[j+1]=temp;  
 }  
 }  

Output

1)create
2)insert
3)delete
4)search
5)print
6)Sort
7)Modify
8)Quit
Enter Your Choice:1

Enter No. of employees:2

enter data(name code salary): John 1 2000
Jenny 2 3000

1)create
2)insert
3)delete
4)search
5)print
6)Sort
7)Modify
8)Quit
Enter Your Choice:2

enter the position(no of records=2):3

enter data(name code salary): Merry 3 5000

John 1 2000
Jenny 2 3000
Merry 3 5000
1)create
2)insert
3)delete
4)search
5)print
6)Sort
7)Modify
8)Quit
Enter Your Choice:3

enter the code : 2

John 1 2000
Merry 3 5000
1)create
2)insert
3)delete
4)search
5)print
6)Sort
7)Modify
8)Quit
Enter Your Choice:4

enter code:3

found at location=2
Merry 3 5000
1)create
2)insert
3)delete
4)search
5)print
6)Sort
7)Modify
8)Quit
Enter Your Choice:5

John 1 2000
Merry 3 5000
1)create
2)insert
3)delete
4)search
5)print
6)Sort
7)Modify
8)Quit
Enter Your Choice:6

John 1 2000
Merry 3 5000
1)create
2)insert
3)delete
4)search
5)print
6)Sort
7)Modify
8)Quit
Enter Your Choice:7

Enter the code : 3

enter data(name code salary): Diya 5 4000

John 1 2000
Diya 5 4000
1)create
2)insert
3)delete
4)search
5)print
6)Sort
7)Modify
8)Quit
Enter the code : 8

 

 

 

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Filed Under: Fundamentals of Datastructure Tagged With: Datastructure Assignments

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